I thought AnyDice would answer this quickly and so it proved. For a single dice the probabilities are straight forward and the roll needing 4s is the best option at 50% hits compared to 38.9% for 5s re-rolling 1. Racking this up to 6 dice vs 6 dice produces these distributions:
So the average score for 5s re-rolling 1s is 2.33 compared to 3.00 for 4s without any rerolls. The probabilities favour the straight roll by 1 hit. This is confirmed if you run the two situations against one another as you would in a combat:
As expected the most likely outcome is a 1 hit loss for the battle group needing 5s to hit and re-rolling 1s. The next most likely is draw followed by a 2 hit loss. To boil it down even further the probabilities are:
Outcome for battle group needing 4s to hit | |||
Outcome | Win | Draw | Lose |
% | 54.2 | 21.1 | 24.7 |
As I’ll explore in a future post, it’s worth noting that the probabilities of extreme results are very low because of the relatively high number of dice involved; in this case 6 a side.
If you want to experiment with this use this link to go straight to an AnyDice page. The code used was:
\Function code\
function: reroll N:n below M:n
{if N < M {result: [highest of d6 and N]} result: N }
\Outputs\
output 6d [{5..6} contains [reroll d6 below 2]] named "A: 5s to hit re-rolling 1s"
output 6d [{4..6} contains [reroll d6 below 1]] named "B: 4s to hit no re-rolls"
output 6d [{5..6} contains [reroll d6 below 2]] - 6d [{4..6} contains [re-roll d6 below 1]] named "A - B"
Thanks once again to Jason Flick for creating AnyDice.
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